Question

Match the following with the type of root we get *

REAL AND DISTINCT, REAL AND EQUAL , NOT REAL
1) 3x²-2X+2=0
2) 2x²-2√6x+3=0
3) 2x²+X-1=0​

Answer 1

Answer:

no it is not possible real

Answer 2

Step-by-step explanation:

1) 3x²-2X+2=0 - Not real roots.

2) 2x²-2√6x+3=0 -Real and equal.

3) 2x²+X-1=0 -Real and distinct.