Question

Material balance for ammonia production fronm synthetic gas n nitrogen hydrogen

Answer 1

This Demonstration carries out the mass balance around the reactor and splitter in order to compute the amount of ammonia produced when chemical equilibrium is reached in the reactor and in the recycle stream.

We assume that:

(1) the splitter separates the product (i.e., ammonia) perfectly from the reactants (i.e., nitrogen and hydrogen); and

(2) the fresh feed contains stoichiometric amounts of nitrogen and hydrogen.

Answer 2

Explanation:

Answer:

This reaction is the synthesis of Ammonia using Nitrogen and Hydrogen gas.

N+H→NH3

We must remember that Nitrogen and Hydrogen are both diatomic molecules in their standard gas form. This adjusts the equation to

N2+H2→NH3

Now we need to adjust coefficients in order to balance the atoms on each side of the equation. Currently we have 2 atoms of nitrogen and 2 atoms of hydrogen on the reactant side and 1 atom of nitrogen and 3 atoms of hydrogen on the product side.

We can balance the hydrogens by placing a coefficient of 2 in front of ammonia and a coefficient of 3 in front of the hydrogen.

N2+3H2→2NH3

This gives us 6 hydrogen on each side and coincidentally the nitrogens now equal 2 on each side.

                                                 or u can follow dis way

N2+ 3H2-----> 2NH3

Explanation:

N2 + H2 -----> NH3

Let us balance this equation by counting the number of atoms on both sides of the arrow.

N2+ H2-----> NH3

N=2 , H=2 N=1, H=3

To balance the number of N atom on Right Hand Side (RHS) , I will add one molecule of N

H3  on RHS

N2+ H2 -----> 2NH3

N=2 , H=2 N=2 , H= 6

To balance the number of H atoms on Left Hand Side (LHS) , I will add two molecules of

H2 on LHS

N2+ H2 -----> 2NH3

N=2 , H=6 N=2 , H= 6