Physics, asked by rachel5, 1 year ago

Material bodies having finite mass cannot attain speed greater or equal to speed of

light. Hence show that photon of light is mass less particle.

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Answered by myrakincsem
1
The Einstein condition E=mc2E=mc2 can be comprehended as a meaning of kinetic mass m. In the event that the molecule is very still, at that point m is the rest mass, and the condition gives the rest vitality. Be that as it may, if the molecule is in movement, the condition is still valid, however m is the "kinetic mass". 
In relativity, the force of a molecule is given by mv, where m is equal to the kinetic mass and v is equal to the speed. 
It can be demonstrated that for particles that have rest mass, the kineetic mass is additionally give by m=γm0m=γm0, where m0m0 is equal to the kinetic mass, and γ=11−β2√γ=11−β2 . (Here ββ is equal to the speed partitioned by the speed of light, v/c.) 
For particles with zero rest mass, this condition gives zero times limitlessness, an uncertain outcome. So it doesn't work in case of photon.
A few physicists need to rethink the significance of "mass" to be "rest mass", and they get extremely resentful about physicists who keep on using the old definition.
Answered by maheshwarinatraj4121
0

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