Question

Mates,
how to solve this?​

Answer 1

Step-by-step explanation:

∠CBE = 180 - ∠ABC

∠CBO = 1/2 ∠CBE (BO is the bisector of ∠CBE)

∠CBO = 1/2 ( 180 - ∠ABC)

= 1/2 x 180 = 90

∠CBO = 90 - 1/2 ∠ABC

= 1/2 x ∠ABC = 1/2∠ABC

∠BCD = 180 - ∠ACD

∠BCO = 1/2 ∠BCD (CO is the bisector of ∠BCD)

∠BCO = 1/2 (180 - ∠ACD)

∠BCO = 90 - 1/2∠ACD

∠BOC = 180 - (∠CBO + ∠BCO)

∠BOC = 180 - (90 - 1/2∠ABC + 90 - 1/2∠ACD)

∠BOC = 180 - 180 + 1/2∠ABC + 1/2∠ACD

∠BOC = 1/2 (∠ABC + ∠ACD)

∠BOC = 1/2 ( 180 - ∠BAC)

(180 - ∠BAC = ∠ABC + ∠ACD)

∠BOC = 90 - 1/2 ∠BAC

HENCE PROVED

PLEASE MARK AS BRAINLIEST

Answer 2

I was not able to type. So pls refer the attachment above. Hope it helps you.