Question

mates please answer this

it's very urgent

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Answer 1

Given:

Potential difference = 330V

Power = 110W

To Find :

Resistance

Solution:

P = V^2 × R

From above formula we can derive -

R = V^2/P

=> R = (330)^2/110

=> R = 108900/ 110

=> R = 990

$\boxed{\boxed{\boxed{\mathfrak{R = 990}}}}$

Now, energy consumed =

E = N × P × T

here, E refers to energy consumed

N refers to number of unit

P refers to power

T refers to time

Given:

Number of bulbs = 3

Power = 110watt

Time = 5 hrs

So,

E =N×P×T

=> E = 3×110×5

=> E = 1650Wh

$\boxed{\boxed{\boxed{\mathfrak{E= 1650Wh}}}}$

Now,

Total cost of electricity =

total energy consumed×cost

Given :

energy consumed = 1650Wh

Cost = 70paise = 0.7 Rs

=> 1650× 0.7

=> Rs 1155

$\boxed{\boxed{\boxed{\mathfrak{Rs 115}}}}$

monthly cost -

=> 1155 × 30

=> 34650 rs.

$\boxed{\boxed{\boxed{\mathfrak{Rs. 34650 }}}}$

Answer 2

Answer:

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