Question

Math 9
Triangle ABC, altitude AK, BD, CE, orthercenter H
a) Proof that KC/KB = (AC^2+BC^2-BA^2) / (BC^2+BA^2-AC^2)

b) we suppose that HK=1/3 AK. Proof that TanB . TanC =3

c) we suppose that the area of triangle ABC is 120cm^2 and BAC angle =60 degree. Caculate the area of ADE triangle

ANY ONE CAN DO THIS, I WILL MARK THAT ANSWER BRAINLIEST!

Answer 1

Here is your answer

answer is

tan3 theta + 2 sin sqr theta - cos theta

hope you understand

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Thank You

Answer 2

aap he bata dete guess what...