Computer Science, asked by sakshamlekhwar24, 19 days ago

Math.ceil(math.cbrt(64)+math.round(6.5))

Answers

Answered by Shivu516
0

Hope it helps ^_^

Please mark my answer as Brainliest :)

Answer:

11

Explanation:

You would have meant this Math.ceil(Math.cbrt(64)+Math.round(6.5));

ceil means ceiling. The smallest integer that is greater than or equal to the given number is called its ceiling.

We can assume this as:

Ceiling of(\sqrt[3]{64}) + Round off(6.5)

= Ceiling of(4) + 7

= 4 + 7

= 11 Ans.

Answered by ItzMeSam35
1

Question:-

Math.ceil(Math.cbrt(64) + Math.round(6.5))

Answer:-

Math Operator(s) used :-

i) Math.ceil() : Math.ceil() returns the double

value that is greater than or equal

to the argument and is equal to

the nearest mathematical integer. Return Type - Double

ii) Math.cbrt() : The java.lang.Math.cbrt () is

used to return the cube root of a

number. Return Type - Double

iii) Math.round() : The Math.round() method rounds

a float or double to the nearest

integer using normal math round

rules (either up or down). Return Type - Integer

So,

Mathematically

Math.ceil(Math.cbrt(64) + Math.round(6.5)) :

Math.round(6.5) = 7

Math.cbrt(64) = 4.0

Now,

Math.ceil(Math.cbrt(64) + Math.round(6.5)) :

Math.ceil(4.0 + 7)

Math.ceil(11.0)

•°• Math.ceil(Math.cbrt(64) + Math.round(6.5)) : 11.0

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