Question

math equation, solve: t²-5t -24

Answer 1

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${t}^{2} - 5t - 24 = 0$

${t}^{2} - 8t + 3t - 24 = 0$

$t(t - 8) + 3(t - 8) = 0$

$(t + 3)(t - 8) = 0$

Therefore,either t+3=0 or t-8=0

$t + 3 = 0$

$t = - 3$

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$t - 8 = 0$

$t = 8$

Hence, roots are 8 and -3.