Question

math
factorise x³–3x²–9x–5​

Answer 1

Answer:

This is the process of the equation given..

Hopefully it will help you..

Answer 2

Given that :

${x}^{3} - 3 {x}^{2} - 9x - 5$

To factorise :

${x}^{3} - 3 {x}^{2} - 9 x - 5 \\ \\ = > {x}^{3} + ( {x}^{2} - 4 {x}^{2}) + ( - 4 x - 5x ) - 5 \\ \\ = > {x}^{3} + {x}^{2} - 4 {x}^{2} - 4x - 5x - 5 \\ \\ = > {x}^{2} (x + 1) - 4x(x + 1) - 5(x + 1) \\ \\ = > (x + 1)( {x}^{2} - 4x - 5) \\ \\ = > (x + 1)( {x}^{2} - 5x + x - 5) \\ \\ = > (x + 1)[x(x - 5) + 1(x - 5)] \\ \\ = > (x + 1)(x - 5)(x + 1) \\ \\ = > {(x + 1)}^{2} (x - 5)$

So, the answer will be

${(x + 1)}^{2} (x - 5)$

Factors of the given polynomial are (x+1), (x+1) and (x-5)

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Hope it helps ☺