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Answered by TooFree
23

Question 17:

First day = 3000

Next day = 3600

Increase = 3600 - 3000 = 600

Rate of increase = 600/3000 x 100 = 20%


Answer: The rate of increase is 20%


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Question 18:

*Assuming the question meant 20% per year


Year 2013 = 10,000 (Given)


There was a decrease of 20% in 2014:

2014 = 10,000 - (0.2 x 10,000) = 8000


There was a decrease of 20% in 2015:

2015 = 8,000 + (0.2 x 8,000) = 6400


Answer: There was 6400 road accidents in 2015

Answered by BloomingBud
10
17. The number of viewers in a book fair on first day was 3000. Next day it increases and reaches 3600. Then find out the rate of increment of viewers.

\boxed{\bold{ Meaning\: \: of\: \: 'increment' \: \:  :  \: \: 'an\: increase'}}

\mathbb{ SOLUTION } :

Total number of viewers on first day = 3000

On second day, number of viewers = 3600

The number of viewers increase in second day was = 3600 - 3000 = 600

\therefore So, 600 viewers were more in second day.

Now,

Rate of increase

 = \frac{increase \: veiwer}{total \: number \: of \: veiwers} \times 100

 = \frac{600}{3000} \times 100

 = 20\%

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19. In year 2013 number of road accidents was 10,000. Traffic Police started a awareness program to prevent road accidents and found it is reduced by 20%. Find the number of road accidents in 2015.

\mathbb{ SOLUTION } :

Number of accidents in the year 2013 = 10000

So, the Traffic Police started aawareness program, and the accidents were reduced to 20%

So,
in 2014,
20\% \: of \: 10000 \\ \\ = \frac{20}{100} \times 10000 \\ \\ = 2000

=> 10000 - 2000 = 8000

now,
in 2015

20\% \: of \: 8000 \\ \\ = \frac{20}{100} \times 8000 \\ \\ = 1600

\therefore 8000 - 1600 = 6400
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