Math hcf and lcm plz solve
Attachments:
Answers
Answered by
0
8= 2×2×2
9= 3×3
12= 2×2×3
15= 3×5
LCM = 2×2×2×3×3×5
= 360
HCF = 2×3×5
=30
Hope it may help u...
9= 3×3
12= 2×2×3
15= 3×5
LCM = 2×2×2×3×3×5
= 360
HCF = 2×3×5
=30
Hope it may help u...
Answered by
1
The question demands the minimum time, so we have to find out LCM ( Common Factor ).
Prime Factorisation –
8 = 2 × 2 × 2 = 2³
9 = 3 × 3 = 3²
12 = 2 × 2 × 3 = 2² × 3¹
15 = 3 × 5 = 3¹ × 5¹
In LCM, we have to take the maximum power of a particular number.
LCM = 2³ × 3² × 5¹ = 8 × 9 × 5 = 360 minutes
So, 360 minutes = 360 / 60 hours = 6 hours
Hence, they all will meet again at
Prime Factorisation –
8 = 2 × 2 × 2 = 2³
9 = 3 × 3 = 3²
12 = 2 × 2 × 3 = 2² × 3¹
15 = 3 × 5 = 3¹ × 5¹
In LCM, we have to take the maximum power of a particular number.
LCM = 2³ × 3² × 5¹ = 8 × 9 × 5 = 360 minutes
So, 360 minutes = 360 / 60 hours = 6 hours
Hence, they all will meet again at
Similar questions