Math:- In the figure, AB = 8, AQ = 6 and QC = 5, find CD
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i dont know ok.. plz forgive
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Given : ABCD is a trapezium AB || CD
AB = 8, AQ = 6 and QC = 5,
To find : CD
Solution:
in ΔAQB and ΔCQD
∠QAB = ∠QCD Alternate angles
∠QBA = ∠QDC Alternate angles
ΔAQB ~ ΔCQD using AA similarity
AQ/CQ = AB / CD
=> 6 / 5 = 8/CD
=> CD = 40/6
=> CD = 20/3
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