Question

math ke hi questions
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Answer 1

Answer:

Ask correctly I can't able to understand yaar

Answer 2

Answer:

2$\sqrt{sinx}$ + C

Step-by-step explanation:

let u= sin(x)

then du/dx = cos(x)

==> dx =  [ 1/cos(x) ] * du

So given equation becomes

$\int\ {\frac{1}{\sqrt{u} } } \, du$

=  $\int\ {u^{-\frac{1}{2} } } \, du$

=  $\frac{u^{\frac{-1}{2} +1 } }{\frac{-1}{2}+1 }$

=   2*$\sqrt{u}$

=  2*$\sqrt{sin(x)}$        as [u=sin(x)]

Since, this is an indefinite integral so it needs an integration constant C

$\int\ {\frac{cos(x)}{\sqrt{sin(x)} } } \, dx$   = 2$\sqrt{sinx}$ + C

Hope it helps.

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