math olympied 8th standard
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Digit at unit place is b
so digit at tens place is (3+b)
Now if we have a 2 digit number say 17, it can be expanded as 1×10 + 7×1
So the number we are going to find can be written as
(3+b)×10 + b×1
=30+10b+b
=30+11b
Hope it helps..... :-)
so digit at tens place is (3+b)
Now if we have a 2 digit number say 17, it can be expanded as 1×10 + 7×1
So the number we are going to find can be written as
(3+b)×10 + b×1
=30+10b+b
=30+11b
Hope it helps..... :-)
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