Question

math please can you help

me

till
question no.

5

Answer 1

x/y=5/3
3x=5y
3x-5y=0.....ek(1)
again
x-y=18
3×eq
3x-3y=54......ek..(2)
eq (1)-(2)
-2y=-54
y=27
put y=27.in eq (1)
3x-27×5=0
x=135/3
x=45;,y=27
is your answer

Answer 2

let the number be "x".
5x and 3x
now there differ is 18
5x - 3x = 18
2x = 18
x = 18/2
x = 9
therefore, 5x = 5 × 9
= 45
3x = 3 × 9
= 27
45 and 27 are the numbers.....

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