Math, asked by munthiphangcho162, 1 month ago

math please help question no.4​

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Answered by yubicaclaude
0

Answer:

iv) p(x) =2x^4 + 3x^3 - 2x^2 - 9x - 12

g(x) = x^2 - 3

= x = √3

p(√3) = 2*(√3)^4 + 3(√3)^3 - 2(√3)^2 - 9(√3) - 12

= 2*9 + 9√3 - 6 - 9√3 - 12

= 18 - 6 - 12

= 18- 6

= 12

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