math plz quick this question's answer
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now, we will do rationalization on both sides for the given three terms of the series.
A= (3root7/root5+root2)x(root5-root2/root5-roo2) = root5root7-root2root7
B= (5root5/root2+root7)x(root2-root7/root2-root7) = root7root5-root2root5
C= (2root2/root7+root5)x(root7-root5/root7-root5) = root2root7-root2root5
therefore, A-B+C = root5root7-root2root7-root5root7+root2root5+root2root7-root2root5= 0 (everything will get cancelled)
so, the value of the series is 0.
now, we will do rationalization on both sides for the given three terms of the series.
A= (3root7/root5+root2)x(root5-root2/root5-roo2) = root5root7-root2root7
B= (5root5/root2+root7)x(root2-root7/root2-root7) = root7root5-root2root5
C= (2root2/root7+root5)x(root7-root5/root7-root5) = root2root7-root2root5
therefore, A-B+C = root5root7-root2root7-root5root7+root2root5+root2root7-root2root5= 0 (everything will get cancelled)
so, the value of the series is 0.
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