Math, asked by anantha0, 1 year ago

Math problem please help​

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Answered by Anonymous
2

Answer:

0

Step-by-step explanation:

First of all, notice that

sin B = sin 90° = 1.

As usual, let a be the side opposite A, b the side opposte B and c the side opposite C.

Then:

cos A = c/b  =>  sec A = 1 / cos A = b/c

sin C = c/b  =>  sec A sin C = 1

tan A = a/c

tan C = c/a => tan A tan C = 1

So...

sec A sin C - tan A tan C = 1 - 1 = 0

=> ( sec A sin C - tan A tan C ) / sin B = 0 / 1 = 0.

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