Math problem please help
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Step-by-step explanation:
First of all, notice that
sin B = sin 90° = 1.
As usual, let a be the side opposite A, b the side opposte B and c the side opposite C.
Then:
cos A = c/b => sec A = 1 / cos A = b/c
sin C = c/b => sec A sin C = 1
tan A = a/c
tan C = c/a => tan A tan C = 1
So...
sec A sin C - tan A tan C = 1 - 1 = 0
=> ( sec A sin C - tan A tan C ) / sin B = 0 / 1 = 0.
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