Math Q-4
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You have to verify Pythagoras theorem here,
(I) PQ^2 + QR^2 = PR^2
(8)^2 + (6)^2 = (10)^2
64 + 36 = 100
100 = 100
Therefore, it is a right angled triangle.
(ii) A^2 + BC^2 = AC^2
(4)^2 + (3)^2 = (5)^2
16 + 9 = 25
25 = 25
Therefore, it is a right angled triangle
(I) PQ^2 + QR^2 = PR^2
(8)^2 + (6)^2 = (10)^2
64 + 36 = 100
100 = 100
Therefore, it is a right angled triangle.
(ii) A^2 + BC^2 = AC^2
(4)^2 + (3)^2 = (5)^2
16 + 9 = 25
25 = 25
Therefore, it is a right angled triangle
Answered by
0
By Pythagoras property
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