math question........
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Heya mate,Here is ur answer
1 ) Given that DE// BC,
Using BPT ( Basic Proportionality Theorem)
AD/DB= AE/EC
1.5/3= 1/EC
By cross multiplication
1.5×EC = 3×1
1.5 EC =3
EC=3/1.5
EC =2 cm.
2)DE//BC
Using BPT
AD/BD = AE/EC
AD/7.2 = 1.8/5.4
By cross multiplication
AD×5.4 =1.8×7.2
AD×5.4=12.96
AD=12.96/5.4
AD=2.4
Warm regards
@Laughterqueen
Be Brainly ✌✌✌
1 ) Given that DE// BC,
Using BPT ( Basic Proportionality Theorem)
AD/DB= AE/EC
1.5/3= 1/EC
By cross multiplication
1.5×EC = 3×1
1.5 EC =3
EC=3/1.5
EC =2 cm.
2)DE//BC
Using BPT
AD/BD = AE/EC
AD/7.2 = 1.8/5.4
By cross multiplication
AD×5.4 =1.8×7.2
AD×5.4=12.96
AD=12.96/5.4
AD=2.4
Warm regards
@Laughterqueen
Be Brainly ✌✌✌
abhishekshukla1789:
thanks
Answered by
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Answer:
i) Given that DE// BC,
Using Basic Proportionality Theorem
AD/DB= AE/EC
so 1.5/3= 1/EC
1.5 × EC = 3×1
EC=3/1.5
EC =2 cm. (answer)
ii) Given that DE// BC,
Using Basic Proportionality Theorem
so AD/DB = AE/EC
AD/7.2 = 1.8/5.4
AD×5.4 =1.8×7.2
AD×5.4=12.96
AD=12.96/5.4
AD=2.4cm (answer)
pls mark as the Brainliest.......... pls.......
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