Question

math question pls solve this ​

Answer 1

6tan

2

θ−

cos

2

θ

6

=6\left(\tan^2\theta-\dfrac{1}{\cos^2\theta}\right)=6(tan

2

θ−

cos

2

θ

1

)

=6\left(\tan^2\theta-\sec^2\theta\right)=6(tan

2

θ−sec

2

θ)

=-6\left(\sec^2\theta-\tan^2\theta\right)=−6(sec

2

θ−tan

2

θ)

=-6(1)=−6(1) (∵sec²θ-tan²θ=1)

=-6=−6