math's question please solve this
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POQ is a straight line
OR is the bisector of the angle POS
OT is the bisector of the angle SOQ
angle POS =x
so,angle SOQ=π-x
as POQ is a straight line
angle POR= angle ROS=x/2
angle SOT= angle TOQ=(π-x)/2
so,angle ROT=angle ROS+ angle SOT
=x/2+(π-x)/2
=x/2+π/2-x/2
=π/2
=90°
so,angle ROT=90°
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