Math show that any positive odd integer is form 6p + 1, or 6q + , or 6q + 5
Answers
Answered by
0
As per Euclid's Division Lemma
If a and b are 2 positive integers, then
a=bq+r
where 0≤r<b Let positive integer be a
And b 6
Hence a 6q +r
(0 ≤r<6)
r is an integer greater than or equal to 0 and less than 6
hence r can be either 0,1,2,3,4 or 5
If a and b are 2 positive integers, then
a=bq+r
where 0≤r<b Let positive integer be a
And b 6
Hence a 6q +r
(0 ≤r<6)
r is an integer greater than or equal to 0 and less than 6
hence r can be either 0,1,2,3,4 or 5
Similar questions