Math, asked by kdeepak2802, 7 days ago

मदरव्हाट इज द एज ऑफ माय सन ​

Answers

Answered by IIGoLDGrAcEII
8

Answer:

Let the age of son be X. Age of mother = 3X.

Five years ago, age of son was X-5, and age of father was 7(X-5)

Five years ago, age of mother was 3X-5, and age of father was 5 years more, that is 3X.

Equating the two expressions, 3X = 7(X-5) = 7X - 35

Therefore 4X = 35, or X = 8.75.

The age of son now is 8.75 years

Step-by-step explanation:

Or

Let mother age = x; non-zero

Let son age = y; non-zero

Then,

Now: x/y = 10/3; or x = 10y/3

After 8 years: (x+8) / (y+8) = 12/5

Substituting x in equation above

(10y/3 +8) / (y+8) = 12/5

Cross multiplying yields

50y/3 + 40 = 12y + 96

Solving for y =12

Then x = 40

Answered by Jiya0071
1

Given:

The average age of Mother and son = 45 yr

Mother and son’s age ratio = 3 : 2

Calculations:

Let the age of Mother be 3x.

Let the age of the son be 2x.

According to the question

⇒ (3x + 2x)/2 = 45

⇒ 5x = 90

⇒ x = 18

Son’s age = 2 × 18 = 36 yrs.

∴ Son’s age is 36 years.

As the average of the ages = 45 years

⇒ Sum of their ages = 45 × 2 = 90 years

⇒ Age of the son = (2/5) × 90 = 36 years

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