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Let her initial savings be 'c' and per day savings be 'm'.
Let the equation be y = mx + c,
where x represents the number of days and y represents the total savings in x days.
According to statement,
Case 1 :-
She saved 540 in two days
⇛ 540 = 2m + c .............(1)
Case 2 :-
She saved 600 in 5 days.
⇛ 600 = 5m + c .........(2)
Subtract (1) from (2), we get
⇛ 600 - 540 = 5m + c - 2m - c
⇛ 60 = 3m
⇛m = 20........(3)
Put (3) in (1), we get
⇛ 540 = 2 × 20 + c
⇛ c = 540 - 40
⇛ c = 500.........(4)
On substituting the values of m and c in (1), we get the required equation of savings.
So, required equation is
Now, to find saving in 10 days, put x = 10 in above equation, we get
⇛ y = 20 × 10 + 500
⇛ y = 700
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