Math, asked by emelycansing, 3 months ago

mathdude help don't answer if you don't know​

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Answered by soujanyaneelam
1

Answer:

ok I will not answer because I don't know the answer

Answered by mathdude500
6

Answer:

Let her initial savings be 'c' and per day savings be 'm'.

Let the equation be y = mx + c,

where x represents the number of days and y represents the total savings in x days.

According to statement,

Case 1 :-

She saved 540 in two days

⇛ 540 = 2m + c .............(1)

Case 2 :-

She saved 600 in 5 days.

⇛ 600 = 5m + c .........(2)

Subtract (1) from (2), we get

⇛ 600 - 540 = 5m + c - 2m - c

⇛ 60 = 3m

⇛m = 20........(3)

Put (3) in (1), we get

⇛ 540 = 2 × 20 + c

⇛ c = 540 - 40

⇛ c = 500.........(4)

On substituting the values of m and c in (1), we get the required equation of savings.

So, required equation is

\large \fcolorbox{black}{cya}{\bf \:y = 20x + 500}

Now, to find saving in 10 days, put x = 10 in above equation, we get

⇛ y = 20 × 10 + 500

⇛ y = 700

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