mathemarical form of thermodynamics is ∆u=2+w it is true or false
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At constant temperature, ΔT=0
∴ΔU=nC
v
ΔT
∴ΔU=q+w=0
q=−w
When work done is zero, w=0
∴ΔU=q+w
∴ΔU=q
In gaseous system, w=PΔV
∴ΔU=q+w
∴ΔU=q+PΔV
When work is done by the system, w is negative.
∴ΔU=q−w
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