Question

mathematically derive the second equation of motion , i.e. s=ut+1/2at^2​

Answer 1

Answer:

s= ut + 1/2 at^2

Explanation:

we know

average velocity = final velocity+ initial velocity / 2

Vav = u+ v /2 (1)

we know Vav = s/ t

s= vav × t (2)

from eq (1) in eq (2)

s = (v+u)t/2 (3)

we know v = u + at

put this value in eq (3)

s= ( u+ at +u) t /2

s=(2u+ at)t /2

s = 2ut + at^ 2 /2

s= 2ut /2 + at^2 /2

s = ut + 1/2 at^2

This is the second equation of motion by mathematical .

I hope you will satisfy with my answer

Answer 2

Answer:

we know

average velocity = final velocity+ initial velocity / 2

Vav = u+ v /2 (1)

we know Vav = s/ t

s= vav × t (2)

from eq (1) in eq (2)

s = (v+u)t/2 (3)

we know v = u + at

put this value in eq (3)

s= ( u+ at +u) t /2

s=(2u+ at)t /2

s = 2ut + at^ 2 /2

s= 2ut /2 + at^2 /2

s = ut + 1/2 at^2

Explanation: