Question

mathematican pls give me answe of my question​

Answer 1

Answer:

1/3

Step-by-step explanation:

Given,

3x = cosec θ

x = (cosec θ)/3    - ------- (1)

Also Given,

cot θ = (3/x)

(1/x) = (cot θ)/3

Now,

3(x² - 1/x²)

= 3[cosec²θ/9 - cot²/9]

= 3[cosec²θ - cot²θ]/9

= (cosec²θ - cot²θ)/3

[∵cosec²θ - cot²θ = 1]

= (1/3)[1]

= (1/3)

Hope it helps!