Question

Mathematics.
Chapter : Exponents
Please Anwer the Questions.​

Answer 1

(1).

$[( \frac{1}{3}) { }^{ - 2} - ( \frac{1}{2} ) {}^{ - 3} + ( \frac{1}{4} ) {}^{ - 4} ] {}^{ - 1} \div 5 {}^{ - 2}$

$[( \frac{3}{1}) {}^{2} - ( \frac{2}{1} ) {}^{3} + ( \frac{4}{1} ) {}^{4} \div( \frac{5}{1} ) {}^{2} ]$

$[ (\frac{9}{1} ) - (\frac{8}{1} ) + (\frac{256}{1} ) \div (\frac{25}{1}) ]$

$\frac{256}{1} \div \frac{25}{1}$

$\frac{256}{1} \times \frac{1}{25} = \frac{256}{25} Answer$

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(2).

$( \frac{1}{2} ) {}^{ - 2} + ( \frac{1}{3} ) {}^{ - 2} + ( \frac{1}{4} ) {}^{ - 2}$

$( \frac{2}{1} ) {}^{2} + ( \frac{3}{1} ){}^{ 2} + ( \frac{4}{1} ) {}^{2}$

$\frac{4}{1} + \frac{9}{1} + \frac{16}{1} = \frac{29}{1} Answer$

Answer 2

Answer:

$(1).</p><p>[tex][( \frac{1}{3}) { }^{ - 2} - ( \frac{1}{2} ) {}^{ - 3} + ( \frac{1}{4} ) {}^{ - 4} ] {}^{ - 1} \div 5 {}^{ - 2}$

$[( \frac{3}{1}) {}^{2} - ( \frac{2}{1} ) {}^{3} + ( \frac{4}{1} ) {}^{4} \div( \frac{5}{1} ) {}^{2} ]$

$[ (\frac{9}{1} ) - (\frac{8}{1} ) + (\frac{256}{1} ) \div (\frac{25}{1}) ]$

$\frac{256}{1} \div \frac{25}{1}$

$\frac{256}{1} \times \frac{1}{25} = \frac{256}{25} Answer$

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(2).

$( \frac{1}{2} ) {}^{ - 2} + ( \frac{1}{3} ) {}^{ - 2} + ( \frac{1}{4} ) {}^{ - 2}$

$( \frac{2}{1} ) {}^{2} + ( \frac{3}{1} ){}^{ 2} + ( \frac{4}{1} ) {}^{2}$

$\frac{4}{1} + \frac{9}{1} + \frac{16}{1} = \frac{29}{1} Answer$