Question

mathematics class 10th 3.7 no. 7
i/ px+qy=p-q
qx-py=p+q
solve this following pair of linear equation​

Answer 1

Step-by-step explanation:

We have ,

px+qy=p-q.....(1)

qx-py=p+q......(2)

Multiplying equation (1)with p and equation (2) with q, we have

p^2x +qpy = p^2-qp .....(3)

and ,

q^2x -pqy= q^2 +qp..... (4)

Adding equation (3) and equation(4), we have

p^2x+q^2x= p^2+q^2

→x(p^2+q^2)=p^2+q^2

→x= 1

Put x=1 in equation (1), we have

p+qy=p-q

→qy=-q

→y=-1

Hence , x=1 and y=-1.