Question

️⚠️ MATHEMATICS EXPERT ONLY
WILL BE BRAINLIEST BY Me

QUES ? THE SUM OF TWO RATIONAL NUMBERS IS -7/12.IF ONE OF THEM IS -13/12 ,FIND THE OTHER ??

DONT WRITE WRONG ANSWER

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Answer 1

Given

• Sum of two irrational numbers = $\sf{\dfrac{-7}{12}}$
• One of the number = $\sf{\dfrac{-13}{12}}$

To find

• The other number

Solution

Let the number x.

According to the question,

$\quad \implies \sf{\dfrac{ - 13}{12} + x = \dfrac{ - 7}{12} } \\\\\\ \quad \implies \sf{x = \dfrac{ - 7}{12} + \dfrac{13}{12}} \\\\ \\ \quad \implies \sf{x = \dfrac{ - 7 + 13}{12}} \\ \\ \\ \quad \implies \sf{ \dfrac{6}{12} } \\ \\ \\ \quad \sf \implies \dfrac{ \not{6}}{ \cancel{12}} \\ \\ \\ \quad \implies \sf \dfrac{1}{2} \\ \\ \\ \quad \mapsto\boxed{ \sf \red{ \dfrac{1}{2}}}\purple{ \bigstar}$

$\therefore$ The number is 1/2.

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Let's verify :-

$\quad \implies \sf{\dfrac{ - 13}{12} + \dfrac{1}{2} } \\ \\ \\ \quad \implies \sf \dfrac{ - 13 + 6}{12} \\ \\ \\ \quad \implies \sf \dfrac{ - 7}{12} \\ \\ \\ \quad \red\bigstar \bf \purple {hence \: verified}$

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Know MorE :-

What is a rational number?

⟶ A number which can be expressed as a/b where a and b are integers and b ≠ 0.

For example - $\sf{\sqrt{16}}$ is rational.

What is an irrational number?

⟶ The square roots, cube roots, etc.. whose exact value cannot be obtained are called irrational numbers.

• For example - $\sf{\sqrt{7}}$ is irrational.

Answer 2

Question :-

• The sum of two rational number is -7/12. If one of them is -13/12. Find the other ?

Given :-

• First number = -13/12
• Sum of the Number = -7/12

To Find :-

• The Second Rational number .

Solution :-

Let the Second Rational number be x

★ According to the Question ★

${:} \longrightarrow \sf{\sf{\dfrac{-13}{12}\: + \: x \: = \: \dfrac{-7}{12} }}$

${:} \longrightarrow \sf{\sf{ x \: = \: \dfrac{-7}{12} \: - \: \bigg(\dfrac{ - 13}{12} \bigg) }}$

${:} \longrightarrow \sf{\sf{ x \: = \: \dfrac{-7}{12} \: + \: \dfrac{ 13}{12} }}$

${:} \longrightarrow \sf{\sf{ x \: = \: \dfrac{-7 \: + \: 13}{12} \: }}$

${:} \longrightarrow \sf{\sf{ x \: = \: \dfrac{6}{12} \: }}$

${:} \longrightarrow \sf{\bf{ x \: = \: \dfrac{1}{2} \: }}$

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Verification :-

$\longmapsto \sf{\sf{\dfrac{-13}{12}\: + \: x \: = \: \dfrac{-7}{12} }}$

$\longmapsto \sf{\sf{\dfrac{-13}{12}\: + \: \dfrac{1}{2} \: = \: \dfrac{-7}{12} }}$

$\longmapsto \sf{\sf{\dfrac{-13 \: + \: 6}{12}\: \: = \: \dfrac{-7}{12} }}$

$\longmapsto \sf{\bf{\dfrac{-7}{12}\: \: = \: \dfrac{-7}{12} }}$

Hence, Verified

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More For Knowledge :-

$\underbrace\red{\boxed{ \sf \green{ Rules \: to \:Solve \: a \: Equation}}}$

• Rule 1 :- Same quantity ( number ) can be added to both side of an equation without changing the equality.
• Rule 2 :- Same quantity can be subtracted from both sides of an equation without changing the quality
• Rule 3 :- Both sides of an equation may be multiplied by the same non zero number without changing the quality.
• Rule 4 :- Both sides of an equation may be divided by the same non zero number without changing the quality.

$\begin{gathered}\\ \\\end{gathered}$

Note :-

• It should be noted that some complicated equation can be solved by using two or more of these rules together.

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