Mathematics for Class VII
2. Find the interest on Rs 500 for a period of 4 years at the rate of 8% per annum. Also, find the
3. A sum of Rs 400 is lent at the rate of 5% per annum. Find the interest at the end of 2 years.
5. A person deposits Rs 25000 in a firm who pays an interest at the rate of 20% per annum
6. A man borrowed Rs 8000 from a bank at 8% per annum. Find the amount he has to pay
7. Rakesh lent out Rs 8000 for 5 years at 15% per annum and borrowed Rs 6000 for 3 years al
8. Anita deposits Rs 1000 in a savings bank account. The bank pays interest at the rate of 5% per
9. Nalini borrowed Rs 550 from her friend at 8% per annum. She returned the amount after 6
10. Rohit borrowed Rs 60000 from a bank at 9% per annum for 2 years. He lent this sum of money
11. Romesh borrowed Rs 2000 at 2% per annum and Rs 1000 at 5% per annum. He cleared hi=
13.8
amount to be paid at the end of the period.
4. A sum of Rs 400 is lent for 3 years at the rate of 6% per annum. Find the interest.
Calculate the income he gets from it annually.
1
after 4
years.
2
12% per annum. How much did he gain or lose?
annum. What amount can Anita get after one year?
months. How much did she pay?
to Rohan at 10% per annum for 2 years. How much did Rohit earn from this transaction?
debt after 2 years by giving Rs 2800 and a watch. What is the cost of the watch?
12. Mr Garg lent Rs 15000 to his friend. He charged 15% per annum on Rs 12500 and 18% ont
rest. How much interest does he earn in 3 years?
13. Shikha deposited Rs 2000 in a bank which pays 6% simple interest. She withdrew Rs 700
the end of first year. What will be her balance after 3 years?
14. Reema took a loan of Rs 8000 from a money lender, who charged interest at the rate of 18
per annum. After 2 years, Reema paid him Rs 10400 and wrist watch to clear the debt. Wha
the price of the watch?
15. Mr Sharma deposited Rs 20000 as a fixed deposit in a bank at 10% per annum. 11 30
deducted as income tax on the interest earned, find his annual income.
Answers
2)Given Principal amount P = Rs 500
Time period T = 4 years
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (500 × 4 × 8)/100
= Rs 160
Amount = Principal amount + Interest
= Rs 500 + 160
= Rs 660
3)Given Principal amount P = Rs 400
Time period T = 2 years
Rate of interest R = 5% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation
we get SI = (400 × 2 × 5)/100 = Rs 40s
5)Given Principal amount P = Rs 25000
Time period T = 1 year
Rate of interest R = 20% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (25000 × 1 × 20)/100 = Rs 5000
6)Given Principal amount P = Rs 8000
Time period T = 4 ½ years = 9/2 years
Rate of interest R = 8% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (8000 × (9/2) × 8)/100 = Rs 2880
Amount = Principal amount + Interest
= Rs 8000 + 2880 = Rs 10880
7)Given Principal amount P = Rs 8000
Time period T = 5 years
Rate of interest R = 15% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (8000 × 5 × 15)/100 = Rs 6000
Principal amount P = Rs 6000
Time period T = 3 years
Rate of interest R = 12% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (6000 × 3 × 12)/100 = Rs 2160
Amount gained by Rakesh = Rs 6000 − Rs 2160
= Rs 3840
8)Given Principal amount P = Rs 1000
Time period T = 1 year
Rate of interest R = 5% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (1000 × 1 × 5)/100 = Rs 50
Total amount paid after 1 year = Principal amount + Interest
= Rs 1000 + Rs 50 = Rs 1050
9)Given Principal amount P = Rs 550
Time period T = ½ year
Rate of interest R = 8% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (550 × ½ × 8)/100
= Rs 22
Total amount paid after ½ year = Principal amount + Interest
= Rs 550 + Rs 22
= Rs 572
10)Given Principal amount P = Rs 60000
Time period T = 2 years
Rate of interest R = 10% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (60000 × 2 × 10)/100 = Rs 12000
Principal amount P = Rs 60000
Time period T = 2 years
Rate of interest R = 9% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (60000 × 2 × 9)/100 = Rs 10800
Amount gained by Rohit = Rs 12000 − Rs 10800
= Rs 1200
11)Given Principal amount P = Rs 2000
Time period T = 2 years
Rate of interest R = 2% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (2000 × 2 × 2)/100 = Rs 80
Principal amount P = Rs 1000
Time period T = 2 years
Rate of interest R = 5% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (1000 × 2 × 5)/100 = Rs 100
Total amount that he will have to return = Rs. 2000 + 1000 + 80 + 100
= Rs. 3180
Amount repaid = Rs. 2800
Value of the watch = Rs. 3180 – 2800 = Rs. 380
12)Given Principal amount P = Rs 15000
Time period T = 3 years
Rate of interest R = 15% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (15000 × 3 × 15)/100 = Rs 5625
Rest of the amount lent = Rs 15000 − Rs 12500
= Rs 2500
Rate of interest = 18 % p.a.
Time period = 3 years
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (2500 × 3 × 18)/100 = Rs 1350
Total interest earned = Rs 5625 + Rs 1350 = Rs 6975
13)Given Principal amount P = Rs 2000
Time period T = 1 year
Rate of interest R = 6% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (2000 × 1 × 6)/100 = Rs 120
So amount after 1 year = Principal amount + Interest
= 2000 + 120 = Rs 2120
after 1 year, amount withdrawn = Rs 700
Principal amount left = Rs 2120 − Rs 700 = Rs 1420
Time period = 2 years
Rate of interest = 6% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (1420 × 2 × 6)/100
Interest after two years = Rs 170.40
Total amount after 3 years = Rs 1420 + Rs 170.40
= Rs 1590.40