MATHEMATICS
If [3(230 + x)]* = 492a04. then a + x is
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12
Step-by-step explanation:
Given
If [3(230 + x)]* = 492a04. then a + x is
Given [3(320 + x)]^2 = 492a04
so (230 + x)^2 = 492a04 / 9
Now 4 + 9 + 2 + a + 0 + 4 = 19 + a
Sum of digits must be divisible by 9, so 19 + 8 = 27 is divisible by 9
Hence a = 8
[3(230 + x)]^2 = 492804
= √492804
3(230 + x) = 702
690 + 3x = 702
So 3x = 702 – 690
So 3x = 12
So x = 4
Now a + x = 8 + 4
Or a + x = 12
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