Math, asked by sanjeev474, 11 months ago

MATHEMATICS
If [3(230 + x)]* = 492a04. then a + x is

Answers

Answered by knjroopa
7

Answer:

12

Step-by-step explanation:

Given  

If [3(230 + x)]* = 492a04. then a + x is

Given [3(320 + x)]^2 = 492a04

so (230 + x)^2 = 492a04 / 9

Now 4 + 9 + 2 + a + 0 + 4 = 19 + a

Sum of digits must be divisible by 9, so 19 + 8 = 27 is divisible by 9

Hence a = 8

[3(230 + x)]^2 = 492804

                      = √492804

     3(230 + x) = 702

      690 + 3x = 702

So 3x = 702 – 690

So 3x = 12

So x = 4

Now a + x = 8 + 4

Or a + x = 12

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