mathematics induction
can anyone solve this question
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Let P(n) be the given equation
P(n) : Given question stated above
Put n = 1
Lhs = 2¹ =2
Rhs = 2( 2¹-1)=2 So lhs =rhs Let P ( 1) is true
Put n = k We have P(k) =
2 +2²+2³+....+2^ k= 2( 2^k - 1 ) Equation 1 Let P(k) be true
Put n = k +1
2+2²+2³+....+2^(k+1)= 2 ( 2^(k+1) - 1 )
2+2²+2³+.....+2^( k )×2= 2 ( 2^(k+1) - 1 )
from equation 1 we have
2(2^k-1 ) ×2 = 2( 2^(k +1) -1 )
lhs = rhs
So P( k+1) is true when P ( k) is true
Therefore by PMI P(n) is true for all n belongs to N
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