Question

mathematics mathematics








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Answer 1

Answer:

which one is to solve

please say

Answer 2

Answer:

1)24/7 2)$\sqrt{3}$-2/3$\sqrt{3}$

Step-by-step explanation:

1. secθ=H/B

tanθ=P/B

P=$\sqrt{H^{2 }-B^{2} }$

2.cosθ=B/H

secθ=1/cosθ

cosecθ=H/P

P=$\sqrt{H^{2 }-B^{2} }$

3. i)$\sqrt{\frac{(1-sinx)(1+sinx)}{(1+sinx)^{2} } }$

=$\sqrt{\frac{cosx^{2} }{(1+sinx)^{2} } }$

=$\frac{cosx}{1+sinx}$

=$\frac{1}{tanx+secx}$

multiply secx-tanx to num. and denom.

=secx-tanx

ii)$\frac{tanx(secx-1)}{(secx+1)(secx-1)}$

=$\frac{tanx(secx-1)}{tanx^{2} }$

=$\frac{secx-1}{tanx}$