Question

Mathematics
Physics
(b+c)
c?
Tc+a)?
g?
6?
= 1 abc(a+b+c) then 1 = ....
>
(a+b)?
В)
1
C) 0
D) 3​

Answer 1

Answer:

a3 + b3 + c3 - 3abc = (a + b + c )(a2 + b2 + c2 -ab - ac -bc) Now it is given that : a3 + b3 + c3 = 3abc. So, a3 + b3 + c3 - 3abc = 0.