mathematics please solve this
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(i) angle E
(ii) DF
(iii) Angle R
(iv) FE
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So given ▲EDF ≅ ▲PQR ,
See the figure above:-
So By CPCT { corresponding parts of congruent triangle }
(i) ∠P
∠P = ∠E
(ii) QR
QR = DF
(iii) ∠R
∠R = ∠F
(iv) RP
RP = EF
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