mathematics problem
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Given - angle AP b is equals to 50 degree
angle PRD is equal to 127 degree
Proof- since a b is parallel to CD and PQ is a transfer shall therefore angle A PQ is equal to angle pqr therefore x is equal to 50
x = 50°
Now an angle PR q is equals to 127 degree - 180 degree because they are on a same line 53 °
Hence by angle sum property of a triangle angle y is equals to 50 + 53 - 180 = 77
hence y= 77°
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