Question

Mathematics

Prove that:
Lim {ae^x+ be^(-x)}/{ce^x + de^(-x)}=a/c,when x tends to infinity

Answer 1

lim               ae^x+be^-x
x tends to ∞  ce^x+de^-x
taking common e^x from nominator as well denominator
lim                e^x(a+be^-2x)
x tends to∞    e^x(c+de^-2x)
Apply limit
a+be^-∞          ⇒a/c    ( e^∞=0 )
c+de^-∞