Mathematics teacher of a school decided to have maximum number of mixed fraction for a team is Section has a accommodate equal number of boys and equal number of girls what is the maximum number of sections of their 372 boys and 444 girls r
Answers
Answered by
31
Answer:
31 Section of 12 Boys
37 Section of 12 Girls
12 sections each with 31 Boys & 37 Girls
Step-by-step explanation:
372 boys and 444 girls
To find Equal number of boys or girls in a section we need to find HCF
372 = 2 * 2 * 3 * 31
444 = 2 * 2 * 3 * 37
31 Section of 12 Boys
37 Section of 12 Girls
Or we can have 12 sections each with 31 Boys & 37 Girls
Answered by
0
Answer:
4
Step-by-step explanation:
Since in each section equal number of boys and girls need to be accomodated, therefore , let us find out HCF of 420 and 272
420=2*2*3*5*7
272=2*2*2*2*17
HCF =2*2=4
Number of boys in each section=420/4=105
Number of girls in each section=272/4=68
TOTAL NUMBER OF SECTIONS ARE 4
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