Math, asked by anshthakur2004, 1 year ago

Mathematics teacher of a school decided to have maximum number of mixed fraction for a team is Section has a accommodate equal number of boys and equal number of girls what is the maximum number of sections of their 372 boys and 444 girls r

Answers

Answered by amitnrw
31

Answer:

31 Section of 12 Boys

37 Section of 12 Girls

12 sections  each with  31 Boys & 37 Girls

Step-by-step explanation:

372 boys and 444 girls

To find Equal number of  boys or girls in a section we need to find HCF

372 = 2 * 2 * 3 * 31

444 = 2 * 2 * 3 * 37

31 Section of 12 Boys

37 Section of 12 Girls

Or we can have 12 sections  each with  31 Boys & 37 Girls

Answered by kessiya
0

Answer:

4

Step-by-step explanation:

Since in each section equal number of boys and girls need to be accomodated, therefore , let us find out HCF of 420 and 272

420=2*2*3*5*7

272=2*2*2*2*17

HCF =2*2=4

Number of boys in each section=420/4=105

Number of girls in each section=272/4=68

TOTAL NUMBER OF SECTIONS ARE 4

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