Mathematicsbook7class
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in triangle ABC ,it is given that angle A is a right angle ,
so,
BC would be the hypotenuse
AB would be the base and
AC would be the height
so we can solve it by simple 1/2*base *height formula
area of triangle=1/2*AB*AC
=1/2*5*12
=5*6
=30m sq.
now we will take BC as base
and AD as height
so,
area of triangle=1/2*BC*AD
30=1/2*13*AD
30*2=13*AD
60/13=AD
AD=4.615cm
so,
BC would be the hypotenuse
AB would be the base and
AC would be the height
so we can solve it by simple 1/2*base *height formula
area of triangle=1/2*AB*AC
=1/2*5*12
=5*6
=30m sq.
now we will take BC as base
and AD as height
so,
area of triangle=1/2*BC*AD
30=1/2*13*AD
30*2=13*AD
60/13=AD
AD=4.615cm
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