Mathew prepared a yellowish green solution of Ferrous Sulphate
in beaker A and placed a copper wire in it. What change will
he observe in the beaker after an hour?
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Answer:
Yellowish green color iron sulphate solution is formed. Beaker B- Copper is less reactive than iron and cannot displace the iron from the ferrous sulphate solution. So, no change is observed.
Explanation:
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He will observe no changes in the beaker after an hour.
- In a reactivity series, the metals that occupy the top position are more reactive than the ones which lie at the bottom.
- Hence, as per the reactivity series Iron lies at a higher position than copper. Therefore, no displacement or change in reaction will be observed as Iron is more reactive than Copper.
- The beaker will remain yellowish-green because of Ferrous sulphate as no reaction will take place.
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