Question

maths .................​

Answer 1

Answer:

MARK M/E BRAINLIEST( I DID SO MUCH FOR YOU I SHOULD DESERVE IT)

Step-by-step explanation:

$\frac{2^{5x\ }}{2^x}=\left(2^{20}\right)^{\frac{1}{5}}$

= 2^5x/2^x= 16

= 2^5x/2^x= 2^4

= 5x - x= 4

= 4x = 4

= x = 1 ( Ans)

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$(2^3)^4=(2^2)^n$

= 2^12= 2^2n

= 12 = 2n

= n = 6 (Ans)

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$\left(\frac{3}{5}\right)^{^x}\cdot \left(\frac{5}{3}\right)^{^{2x}}=\ \frac{125}{27}$

= ((5/3)^-x) . ((5/3)^2x)= 125/27

=((5/3)^-x) . ((5/3)^2x)= ((5/3)^3)

= 2x-x= 3

= x = 3 ( Ans)

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$2^{\left(n-7\right)}\cdot 5^{\left(n-4\right)}=\ 1250$

= 2^(n-7) . 5^(n-4) = 5^4 . 2^1

= n-7 = 1

 n-4 = 4

= n = 8 ( Ans)

[NOTE :- IF BOTH THE EQUATION HAD NON- EQUAL SOLUTIONS THE SUM IS WRONG]

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$2^{\left(n-5\right)}\cdot 5^{\left(n-4\right)}=\ 5$

= 2^(n-5) . 5^(n-4) = 5^1 . 2^0

= n-5 = 0

  n-4 = 1

= n= 5 (Ans)

[NOTE :- IF BOTH THE EQUATION HAD NON- EQUAL SOLUTIONS THE SUM IS WRONG]

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$5^{\left(n-2\right)}\cdot 3^{\left(2n-3\right)}=\ 135$

= 5^(n-2) . 3^(2n-3)= 5^1 . 3^3

= n-2 = 1

  2n-3 = 3

= n= 3

[NOTE :- IF BOTH THE EQUATION HAD NON- EQUAL SOLUTIONS THE SUM IS WRONG]