maths 2 problem plz help
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Step-by-step explanation:
Given
ΔABC∼ΔPQR
A(ΔABC)=80
A(ΔPQR)=125
According to theorem of areas of similar triangles ""When two triangles are similar, the ratio of areas of those triangles is equal to the ratio of the square of their corresponding sides'
∴
A(ΔPQR)
A(ΔABC)
=
PQ
2
AB
2
⇒
125
80
=
PQ
2
AB
2
25
16
=
PQ
2
AB
2
⇒
5
2
4
2
=
PQ
2
AB
2
⇒
PQ
AB
=
5
4
Therefore,
A(ΔPQR)
A(ΔABC)
=
125
80
and
PQ
AB
=
5
4
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