Question

maths 2111111112111111111​

Answer 1

Answer:

use (tan theta +cot theta)^2 formula

Step-by-step explanation:

you will get the answer

Answer 2

$\orange{ \boxed{\boxed{\begin{array}{cc}\rm \to \:given \: \\ \\ \hookrightarrow \: \rm \: tan \theta + cot\theta = 2 \\ \\ \sf \: we \: have \: to \: find \: value \: of: \\ \\ \hookrightarrow \: \rm {tan}^{2} \theta + cot { }^{2} \theta \\ \\ \\ \pink{ {\boxed{\begin{array}{cc}\rm \: we \: know \: that \\ \\ \hookrightarrow \rm \: {x}^{2} + {y}^{2} = {(x + y)}^{2} - 2xy \\ \end{array}}}} \\ \\ \small{\rm {tan}^{2}\theta + {cot}^{2}\theta = {(tan\theta + cot\theta)}^{2} - 2tan\theta.cot\theta } \\ \\ \rm = {2}^{2} - 2 \times \cancel{ tan\theta }\times \frac{1}{ \cancel{tan\theta}} \\ \\ = 4 - 2 \\ \\ = 2 \end{array}}}}</p><p>$

So, option (A) 2 is the correct answer