Maths
3 Find the smallest number which when
divided by 28, 35 and 42 gives
remainder
5 in every time
Answers
Given : Number which when divided by 28 ,35 and 42 gives a remainder 5 of every time.
To Find : the smallest number
Solution:
the smallest number which when divided by 28 ,35 and 42 gives a remainder 5 of every time.
= LCM (28 , 35 , 42) + 5
LCM - Least common multiplier of given numbers is the least number which is perfectly divisible by given numbers.
LCM = product of each factor of highest power
28 = 2 * 2 * 7
35 = 5 * 7
42 = 2 * 3 * 7
LCM = 2 * 2 * 3 * 5 * 7
= 420
420 + 5 = 425
425 is the smallest number which when divided by 28 ,35 and 42 gives a remainder 5 of every time.
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Answer:
The smallest number which when divided by 28,35 and 42 gives a remainder 5 of every time.
= LCM (28,35,42) +5
LCM Least common multiplier of given numbers is the least number which is perfectly divisible by given numbers.
LCM = product of each factor of highest power
28 = 2 * 2 * 7
35 = 5 * 7
42 = 2*3*7
LCM = 2 * 2*3*5*7
= 420
420 + 5 = 425
425 is the smallest number which when divided by 28,35 and 42 gives a remainder 5 of every time.