Maths 50 Marks
Please provide steps.
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First of all Im very sorry for my mistake in the previous answer. I Corrected it ..but Im deeply sorry and apologize for guiding you towards a wring aproach
Hi..there are many methods to approach a question like this..but aince you havent mention any specific approach , I will use logarithems and their properties to solve this one..i hope you have good understanding on the basics of properties of logarithems
Now..first of all lets use a substitution
(5 + 2√6)^(x^2 -8) = a
(5 + 2√6)^(x^2 -8) = b
Then we can simplify our equation as
a + b = 10 -----(1)
Now using the definition if logarithems ..we can write
log_ (5 + 2√6) a = x^2 -8 -----(2)
log _ (5 - 2√6) b = x^2 -8 -----(3)
[ i.e , if a^b = x..the log_a x = b ]
Now
(2) × (3)
[ log_ (5 + 2√6) a ] × [ log_ (5 - 2√6) b ]
= (x^2 -8)^2
Now..i hope you know that
log_a b = log_c b / log_c a
Using that property we can arrive at ..
[lg a / lg (5 + 2√6) ] [ lg b / lg (5 - 2√6) ] = (x^2 -8)^2
Which means
( lg a × lg b) / [lg(5 + 2√6)× (5 - 2√6) ] = (x^2 -8)^2
Now lets use the property
log a × log b = log (a+b)
[lg (a +b) ] / [ lg (5 + 2√6 + 5 - 2√6) ] = (x^2 -8)^2
Now from (1) we know that a+b =10..using that we can simplify the l.h.s to be equal to 1 !!!
( I leave that simplification up to you..but if you need any help there..please let me know :) )
now the things are really simple
(x^2 -8)^2 = 1
this is a polynomial of 4th degree..so this should have 4 solutions
if we solve this one...
(x^2 -8) = ±1
considering +1
×^2 - 8 = 1
x^2 = 9
x = ± 3
considering -1
x^2 -8 = -1
x^2 =7
x =±√7
now we have all 4 answers !!
i.e :
x = 3 , x= -3 , x =√7 , x = -√7
now the 2nd part should be very easy
for the 3rd part..it says if
-3<x≤ 5
what would be the value of x..
since we know all the possible values if x..you should be able to find the answer easily :)
hope this will help you..please comment if you need any help :)
Hi..there are many methods to approach a question like this..but aince you havent mention any specific approach , I will use logarithems and their properties to solve this one..i hope you have good understanding on the basics of properties of logarithems
Now..first of all lets use a substitution
(5 + 2√6)^(x^2 -8) = a
(5 + 2√6)^(x^2 -8) = b
Then we can simplify our equation as
a + b = 10 -----(1)
Now using the definition if logarithems ..we can write
log_ (5 + 2√6) a = x^2 -8 -----(2)
log _ (5 - 2√6) b = x^2 -8 -----(3)
[ i.e , if a^b = x..the log_a x = b ]
Now
(2) × (3)
[ log_ (5 + 2√6) a ] × [ log_ (5 - 2√6) b ]
= (x^2 -8)^2
Now..i hope you know that
log_a b = log_c b / log_c a
Using that property we can arrive at ..
[lg a / lg (5 + 2√6) ] [ lg b / lg (5 - 2√6) ] = (x^2 -8)^2
Which means
( lg a × lg b) / [lg(5 + 2√6)× (5 - 2√6) ] = (x^2 -8)^2
Now lets use the property
log a × log b = log (a+b)
[lg (a +b) ] / [ lg (5 + 2√6 + 5 - 2√6) ] = (x^2 -8)^2
Now from (1) we know that a+b =10..using that we can simplify the l.h.s to be equal to 1 !!!
( I leave that simplification up to you..but if you need any help there..please let me know :) )
now the things are really simple
(x^2 -8)^2 = 1
this is a polynomial of 4th degree..so this should have 4 solutions
if we solve this one...
(x^2 -8) = ±1
considering +1
×^2 - 8 = 1
x^2 = 9
x = ± 3
considering -1
x^2 -8 = -1
x^2 =7
x =±√7
now we have all 4 answers !!
i.e :
x = 3 , x= -3 , x =√7 , x = -√7
now the 2nd part should be very easy
for the 3rd part..it says if
-3<x≤ 5
what would be the value of x..
since we know all the possible values if x..you should be able to find the answer easily :)
hope this will help you..please comment if you need any help :)
DeFalt:
but the property of log (a-b) : log a/ log b seems incorrect
Consider
5^2 -(2 √6)^ 2 = ( 5 + 2 √6)( 5 - 2 √6)
25 - 24 = ( 5 + 2 √6)( 5 - 2 √6)
1 = ( 5 + 2 √6)( 5 - 2 √6)
Now
( 5 + 2 √6) = 1/ ( 5 - 2 √6) -------(1)
We can substitute it in the 1st equation and get
[ 1/ ( 5 - 2 √6)]^(x^2 -8) + ( 5 - 2 √6)^(x^2 -8) = 10
Lets substitute
( 5 - 2 √6)^(x^2 -8) = t
1/t + t =10
t^2 -10t +1 =0
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