Maths
A hollow sphere of external and internal diameters 8cm and 4cm respectively is melted into a cone of base diameter 8 cm.
Find the height of the cone.
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Answer:
V.OF SPHERE=4/3 PIE ( R cube - r cube)
And v.of cone=1/3 pie R square h.
V.of sphere = v.of cone.
4/3*22/7*(4*4*4-2*2*2)=
1/3*22/7*4*4*4h
4(64-8)=16*h
4*56=16*h
h=(4*56)/16
h=14 cm. ANS.
Thanks for the question
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