Maths
A invests RS 8000 and B invests Rs 11000 at the same rate of interest per annum. If at the end of 3 yrs , B get Rs 720 more interest than A; find the rate of interest.
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Answer:
Step-by-step explanation:
Required formula:
S.I. =
A invested = Rs. 8000
B invested = Rs. 11000
Time period of investment for both A & B, T = 3 years
Let the rate of interest in both the investment be “R”% and the interest earned by A and B be denoted as “Ia” & “Ib” respectively.
Interest earned by A after 3 years:
Ia = = 240R …… (i)
And,
Interest earned by B after 3 years:
Ib = = 330R …… (ii)
It is given that at the end of 3 years the interest earned by B is Rs. 720 more than the interest earned by A, so we can write the eq. as,
Ib = Ia + 720
⇒ 330R = 240R + 720 ……. [substituting values from (i) & (ii)]
⇒ 90R = 720
⇒ R = 720/90
⇒ R = 8%
Thus, the rate of interest is 8%.
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