Question

maths- abcd is a parallelogram. e and f are the mid point of the sides ab and CD respectively. prove

Answer 1

please mark brainliest

Answer 2

Given: ABCD is a parallelogram
AE=BE
CF=DF

To prove: AF&EC trisect diagonal BD.

Proof: DC || AB & DC=AB
So, FC=AE(Mid-point) & FC || AB
In ∆DQC,
CF=DF
PF || QC
So, by the Mid-point theorem,
DP=PQ -------------------- (1)
In ∆APB,
AE=BF
EQ || AP
So, by the Mid-point theorem,
PQ=BQ -------------------- (2)
By (1) & (2),
DP=PQ=BQ
Hence proved.